题目描述#
给定一个
数据保证你能从
输入格式#
第一行为三个正整数
输出格式#
输出一行
样例#
样例输入 #1#
4 6 1
1 2 2
2 3 2
2 4 1
1 3 5
3 4 3
1 4 4plaintext样例输出 #1#
0 2 4 3plaintext提示#
算法分析#
使用堆优化(优先队列)
struct Qnode{
int w;
int po;
inline bool operator <(const Qnode &x)const{
return w>x.w;
}
};
priority_queue<Qnode>q;cpp初始化dis为极大值
for(int i = 1;i<=n;i++) dis[i]=2147483647;
dis[f]=0;cpp主体
dis[f]=0;
q.push((Qnode){0,f});
while(!q.empty()){
Qnode now =q.top();q.pop();
int u=now.po;
if(vis[u]) continue;
vis[u]=1;
if(road[u].size()){
for(int i = 0;i<=road[u].size()-1;i++){
if(dis[road[u][i].to]>dis[u]+road[u][i].val){
dis[road[u][i].to]=dis[u]+road[u][i].val;//更新路径
pre[road[u][i].to]=u;
q.push((Qnode){dis[road[u][i].to],road[u][i].to});
}
}
}
}cppModel#
#include<iostream>
#include<vector>
#include<queue>
using namespace std;
struct node{
int to;
int val;
};
struct Qnode{
int w;
int po;
inline bool operator <(const Qnode &x)const{
return w>x.w;
}
};
priority_queue<Qnode>q;
vector <node> road[100004];
int vis[100004],pre[100004];
int dis[100004];
int main(){
int n,m,f,u,v,w;
scanf("%d%d%d",&n,&m,&f);
for(int i = 1;i<=m;i++){
scanf("%d%d%d",&u,&v,&w);
road[u].push_back(node{v,w});
}
for(int i = 1;i<=n;i++) dis[i]=2147483647;
dis[f]=0;
q.push((Qnode){0,f});
while(!q.empty()){
Qnode now =q.top();q.pop();
int u=now.po;
if(vis[u])continue;
vis[u]=1;
if(road[u].size()){
for(int i = 0;i<=road[u].size()-1;i++){
if(dis[road[u][i].to]>dis[u]+road[u][i].val){
dis[road[u][i].to]=dis[u]+road[u][i].val;
pre[road[u][i].to]=u;
q.push((Qnode){dis[road[u][i].to],road[u][i].to});
}
}
}
}
for(int i=1;i<=n;i++){
printf("%d ",dis[i]);
}
return 0;
}cpp
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